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An electric motor has specifications: voltage is 380 V, 3 phase, frequency is 50 Hz, 1500 rpm, cos phi is 0.8 and real power on the name plate is 22 kW. Convert to HP (Horse Power) and calculate, how many current of electricity will flow into the motor?
Connection of 3-Phase Motor

:catat: Answer:
1HP = 0.75 kW --> 22 kW / 0.75 kW x 1 HP = 29.33 HP
--> 22 kW ≈ 30 HP
:catat: The power of the motor is 30 HP

V = 380 V 3 fase
f = 50 Hz
Cos φ = 0.8
P = 22 kW = 22000 W
I = ...?

The formula of real power electricity in 3-phase:
P = √3 x V x I x Cos φ --> I = P / (√3 x V x Cos φ)
--> I = 22000 / (√3 x 380 x 0.8)
--> I = 41.78 A
:catat: The current of electricity will flow into the motor is 41,78 A

For reference, here is a table of the electric currents of a 3-phase motor, 380 V, cos phi 0.8

kWHPA
0.40.50.8
0.7511.4
1.11.52.1
1.522.8
2.234.2
345.7
3.757
4.568.5
5.57.510.4
7.51014.2
91217.1
111520.9
152028.5
18.52535.1
223041.8
304057
375070.3
456085.5
5575104.5
75100142.4

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